Mathematics Algebraic Expressions Questions And Answers
Algebraic Expressions Questions and Answers - Form 1 Topical Mathematics
Questions
- Five years ago, a mother's age was four times that of her daughter. In four years to come, she will be 2 ½ times the age of her daughter. Calculate the sum of their present ages
- Simplify;
- 6a – 2b + 7a – 4b + 2
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- Simplify
- Given that x + y = 8 and x2 + y2 = 34
Find;- the value of x2 + 2xy + y2
- Find the value of ; 2xy
- x2 – 2xy + y2
- Value of x and y
- Simplify the expression.
- Simplify the expression
2/3(3x -2) – 3/4(2x -2) - Simplify by factorizing completely:
- Simplify as far as possible.
- Simplify:
-
- hence solve:-
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- Factorize completely the expression
75x2 – 27y2 - Simplify
- Simplify the expression:-
- Given that (x-3) (Ax2+bx+c) = x3-7x-6, find the value of A, B and C
- solve for y in 8x(22)y=6x2y-1
- Simplify completely
- Simplify the expression.:
- Simplify
- The sum of two numbers is 15. The difference between five times the first number and three times the second number is 19. Find the two numbers.
- Simplify the following expressions by reducing it to a single fraction
- Simplify the expression:-
Answers
- Let the daughter's age 5yrs ago be x
Mother 4x
come;
Daughter = x + 9
Mother = 4x+ 9
4x + 9 = 5/2(x +9)
4x + 9 = 2.5x + 22.5
1.5x = 13.5
x = 9
Mother = 41yrs
14 + 41 =55 - 6a + 7a – 2b – 4b + 2
= 13a – 6b + 2 -
- 6a + 7a – 2b – 4b + 2
-
- From x + y and x2 + y2 = 34
X = 8 – y
Substituting for x in x2 – y2 = 34
(8 – y) (8 – y) + y2 = 34
64 – 8y – 8y + y2 + y2 = 34
64 – 16y + 2y2 = 34
2y2 – 16y + 64 – 34 = 0
2y2 – 16y + 30 = 0
y2 = 8y + 15 = 0
y (y – 3) – 5 (y-3) = 0 (y-5) (y – 3)
y is either 5 or 3
but x – y = 8
x is either 5 0r 3
x2 + 2xy + y2 = 32 + 2 x 3 x 5 + 25
= 9 + 30 + 25 = 64 - 2xy = 2 x 3 x 5 = 30
- x2 – 2xy + y2 = 9 – 2 x 3 x 5 + 25 = 4
- x - y = 8 and x2 + y2 = 34
x = 8 – y
(8 – y)2 + y2 = 34
y2 – 8y + 15 = 0
y2 – 3y – 5y + 15 = 0
y(y -3) – 5(y – 3)
(y-3) = 0 y = 3
(y-5) = 0 y = 5
x + 3 = 8, x = 5 or x + 5 = 8
x = 3
x is either 3 or 5
y is either 3 or 5
- From x + y and x2 + y2 = 34
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-
-
-
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- 3( 25x2 – 9y2)
3(5x + 3y)(5x – 3y) - Factorizing the numerator
= p(p2 – q2) + q(p2-q)
= (p+q) (p2-q2)
= (p+q) (p+q) n(p-q)
Factorising the denominator
(p+q) (p+q)
Numerator = p - q
Denominator - ( 3x + 2y ) ( 3x - 2y )
( 3x + 2y ) ( 3x - 2y )
3x + 2y
4x + 3y - (x – 3) (AX2 +BX + C) = x3 – 7x – 6
AX3 + BX2 +CX – 3AX2 – 3BX – 3c = x3 – 7x – 6
A = 1
B – 3A = 0
B – 3 x 1 = 0
B = 3
-3c = -6
c = 2 - 8(22)y = 6 x 2y – 1
let t = 2y
8t2 = 6t – 1
8t2 – 4t – 2t + 1 = 0
(4t – 1) (2t – 1) = 0
t = ¼ or ½
t = 2y = ¼ = 2-2
y = -2
or t = 2y = ½ = 2-1
y = -1
y = -2 or -1 -
- 8(22)y = 6 x 2y – 1
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- Let the numbers be a and b
a + b = 15 x3
5a – 3b = 19 x 13a + 3b = 45
5a – 3b = 19
8a = 64
a = 8
b = 7 -
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Mathematics Algebraic Expressions Questions And Answers
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